Area and perimeter project: design a dream bedroom, grades 3–5

1. Set the rules. Each bedroom is a rectangle no bigger than 12 by 14 squares. Students pick the size and write it as "length times width". Ask: "If your room is 12 by 10, how many square feet of carpet do you need?"
2. Students trace the outer walls and find the perimeter: add all four sides. Then they find the area by counting rows or multiplying. Have them write both with units: 44 feet and 120 square feet.
3. Add furniture, each one a rectangle drawn on the grid: a bed (4 by 6 is about twin size), a desk, a dresser, and one dream item they invent, such as a reading nook or a climbing wall.
4. For each item, students label its area in square feet.
5. Find the open floor: room area minus the total furniture area.
6. Gallery walk. Partners trade plans and check one area and one perimeter, initialing what they checked.

Twist for the end: give each student a "remodel": "Your room must keep the same area but get a bigger perimeter." Students discover that long, skinny rectangles have larger perimeters than square ones with the same area.

Differentiation: for students who need support, give a fixed 10 by 10 room and three furniture pieces, and count squares before multiplying. For advanced students, add a budget (carpet costs $3 per square foot, trim costs $2 per foot). For English learners, post area, perimeter, square feet and length with a small drawing of each, and use the frame "The area of my ___ is ___ square feet." For students with fine-motor or visual needs, use larger grid squares, square tiles or sticky notes instead of drawing, and let them dictate labels.

Quick check: on an exit slip, draw a 3 by 5 rug and write its area and perimeter with the correct units.

If you try it, tell us the most surprising dream item your students added and what it did to their open floor space.